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re: Can this 747 take off?
Posted on 4/13/24 at 9:47 pm to Street Hawk
Posted on 4/13/24 at 9:47 pm to Street Hawk
how is this thing 25 pages long now?
If the belt speed matches the wheel speed 1 for 1 but in the opposite direction then the plane would never move in a forward direction, hence not enough airflow across the wings so it can not take off because it is not moving along the x axis
And adding thrust as a forward vector does not count because the wheels only roll forward as a result of that vector. If the forward vector from engine thrust is combined with the equal vector in the opposite direction from the treadmill motion then the net vector is 0
If the belt speed matches the wheel speed 1 for 1 but in the opposite direction then the plane would never move in a forward direction, hence not enough airflow across the wings so it can not take off because it is not moving along the x axis
And adding thrust as a forward vector does not count because the wheels only roll forward as a result of that vector. If the forward vector from engine thrust is combined with the equal vector in the opposite direction from the treadmill motion then the net vector is 0
This post was edited on 4/13/24 at 9:53 pm
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