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re: OT Geniuses, How would you answer this BlackRock interview question?
Posted on 7/13/24 at 3:01 pm to idlewatcher
Posted on 7/13/24 at 3:01 pm to idlewatcher
the answer is in the question
christ almighty
christ almighty
0
Posted on 7/13/24 at 3:01 pm to boomtown143
None of them will attempt to escape. Everyone has a 100% probability of dying
Posted on 7/13/24 at 3:01 pm to supadave3
ChatGPT:
To stop the 100 murderers from escaping, you need to create a situation where each murderer is certain of death if they try to escape. Here’s how you can achieve that:
1. **Line them up:** Arrange the 100 murderers in a single file line.
2. **Number them:** Assign a number to each murderer from 1 to 100.
3. **Make an announcement:** Announce to the murderers that you will randomly choose one murderer to shoot.
4. **Random choice:** Use a random method (like drawing lots or using a random number generator) to choose one murderer to shoot.
The key here is the element of randomness. Because you have made it clear that one random murderer will be chosen and shot, each murderer will perceive a 1% chance of being the one shot if they try to escape. Since you only have one bullet, they will calculate that they have a 99% chance of survival if they do not try to escape, because the bullet can only kill one of them, not more.
Since all murderers are rational and value their lives, they will conclude that staying put gives them a higher chance of survival than trying to escape. This way, the certainty of death if they try to escape (since they believe one of them will be randomly chosen and shot) prevents them from making an escape attempt.
In summary:
- **Random selection:** By announcing and demonstrating that you will randomly select one murderer to shoot, each murderer understands that their chance of being shot is higher if they try to escape (since that would increase the likelihood of being the one chosen to be shot).
- **Certainty of death in attempt:** They all perceive a non-zero probability of being the one who is shot if they attempt to escape, creating a deterrent against escape attempts.
Thus, rational fear of being the one chosen to be shot if they try to escape will keep all 100 murderers from attempting an escape.
To stop the 100 murderers from escaping, you need to create a situation where each murderer is certain of death if they try to escape. Here’s how you can achieve that:
1. **Line them up:** Arrange the 100 murderers in a single file line.
2. **Number them:** Assign a number to each murderer from 1 to 100.
3. **Make an announcement:** Announce to the murderers that you will randomly choose one murderer to shoot.
4. **Random choice:** Use a random method (like drawing lots or using a random number generator) to choose one murderer to shoot.
The key here is the element of randomness. Because you have made it clear that one random murderer will be chosen and shot, each murderer will perceive a 1% chance of being the one shot if they try to escape. Since you only have one bullet, they will calculate that they have a 99% chance of survival if they do not try to escape, because the bullet can only kill one of them, not more.
Since all murderers are rational and value their lives, they will conclude that staying put gives them a higher chance of survival than trying to escape. This way, the certainty of death if they try to escape (since they believe one of them will be randomly chosen and shot) prevents them from making an escape attempt.
In summary:
- **Random selection:** By announcing and demonstrating that you will randomly select one murderer to shoot, each murderer understands that their chance of being shot is higher if they try to escape (since that would increase the likelihood of being the one chosen to be shot).
- **Certainty of death in attempt:** They all perceive a non-zero probability of being the one who is shot if they attempt to escape, creating a deterrent against escape attempts.
Thus, rational fear of being the one chosen to be shot if they try to escape will keep all 100 murderers from attempting an escape.
Posted on 7/13/24 at 3:03 pm to boomtown143
I would shoot Toby twice
Posted on 7/13/24 at 3:05 pm to boomtown143
Take my NRA sharpshooter certificate and make 100 copies. Pass out copies to the murderers.
Posted on 7/13/24 at 3:06 pm to TJack
quote:
Since all murderers are rational
chatgpt is dum
Posted on 7/13/24 at 3:07 pm to TJack
I like that answer. If anyone tries to escape, randomly shoot one.
Posted on 7/13/24 at 3:19 pm to boomtown143
Let them all go. They are only in prison because of systemic racism. The fact that they haven’t been afforded the same opportunities as me a man with white privilege has put them in this situation.
All the white murderers would have to stay though so they can atone for their whiteness.
(I could probably get at least a C-Suite level job with that answer)
All the white murderers would have to stay though so they can atone for their whiteness.
(I could probably get at least a C-Suite level job with that answer)
Posted on 7/13/24 at 3:22 pm to boomtown143
Tell them it's a battle to the death and the last man alive will be set free
Shoot the last man alive
Edit: actual answer I believe is tell them the first person to attempt escape will be shot and have 0 chance of survival. By the rule of the question, no one will be the 1st and therefore no one will escape
Shoot the last man alive
Edit: actual answer I believe is tell them the first person to attempt escape will be shot and have 0 chance of survival. By the rule of the question, no one will be the 1st and therefore no one will escape
This post was edited on 7/13/24 at 3:31 pm
Posted on 7/13/24 at 3:28 pm to boomtown143
Too easy. Gather them all together and pick one at random and tell them to step forward. Walk up and head shot them at point blank range. Tell the other 99 that’s what happens to you if you try to escape.
Posted on 7/13/24 at 3:29 pm to Art Vandelay
quote:
They don’t know you only have 1 round
Exactly.
If they know, then every murderer has a 99% chance of escaping and they all run.
If you're really lucky you can kill 2 with one round and 98 escape.
Posted on 7/13/24 at 3:29 pm to ronricks
quote:u have Officer material written all over u
ronricks
Posted on 7/13/24 at 3:30 pm to boomtown143
Do they know you have a single bullet? That makes a difference in the analysis.
Posted on 7/13/24 at 3:31 pm to OWLFAN86
quote:yep, shoot the one you like the least
Just pick someone out and shoot them and say let that be an example
Posted on 7/13/24 at 3:33 pm to OWLFAN86
Give each prisoner a number. Tell them if one tries to escape, you will shoot the prisoner one number above them. 100 is tied to the 1st. Ideally, each prisoner keeps the prisoner below them in check.
Posted on 7/13/24 at 3:34 pm to boomtown143
My first question would be weather the murderers know I only have one bullet. If they do, it honestly doesn't matter, because nothing you can threaten will bring their chance of escape to zero. Because of the way the question is framed, that's a failure condition.
Assuming they don't know that I only have one round, I fire my one shot in the air and tell them anyone who so much as looks towards the edge of the field gets the next one in the head.
Not as dramatic as shooting someone with that one round, but killing one randomly and for no apparently reason would make the others more likely to try to escape, not less. If I shoot in the air, they are practically certain they are safe as long as they stay in the field. If I kill one, they now believe there is a chance they will die even if they stay.
The entire paradigm of control is predicated on a bluff, so the bluff might as well be as constructive as possible.
Assuming they don't know that I only have one round, I fire my one shot in the air and tell them anyone who so much as looks towards the edge of the field gets the next one in the head.
Not as dramatic as shooting someone with that one round, but killing one randomly and for no apparently reason would make the others more likely to try to escape, not less. If I shoot in the air, they are practically certain they are safe as long as they stay in the field. If I kill one, they now believe there is a chance they will die even if they stay.
The entire paradigm of control is predicated on a bluff, so the bluff might as well be as constructive as possible.
Posted on 7/13/24 at 3:35 pm to boomtown143
You have to use the threat of the murderers against them, not the bullet.
Posted on 7/13/24 at 3:38 pm to TJack
quote:
each murderer will perceive a 1% chance of being the one shot if they try to escape. Since you only have one bullet, they will calculate that they have a 99% chance of survival if they do not try to escape
The question deals with this by saying any probability over 0% will have them escape.
Posted on 7/13/24 at 3:39 pm to boomtown143
To prevent the murderers from escaping, you can follow this strategy:
1. Randomly select two murderers.
2. Shoot one of them with the bullet.
3. If the shot murderer is injured, the other murderer will be certain of injury and won't attempt to escape.
4. If the shot murderer is not injured, the other murderer will have a non-zero probability of injury and won't risk escaping.
This way, you maintain control over the situation and discourage any escape attempts.
1. Randomly select two murderers.
2. Shoot one of them with the bullet.
3. If the shot murderer is injured, the other murderer will be certain of injury and won't attempt to escape.
4. If the shot murderer is not injured, the other murderer will have a non-zero probability of injury and won't risk escaping.
This way, you maintain control over the situation and discourage any escape attempts.
Posted on 7/13/24 at 3:39 pm to Art Vandelay
quote:Don’t wait for one to try.
Make sure you head shot the first one to try. They don’t know you only have 1 round
Pick one at random and execute him.
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